x^2+72+6x=180

Solution for x^2+72+6x=180 equation:

x^2+72+6x=180

We move all terms to the left:

x^2+72+6x-(180)=0

We add all the numbers together, and all the variables

x^2+6x-108=0

a = 1; b = 6; c = -108;
Δ = b2-4ac
Δ = 62-4·1·(-108)
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{13}}{2*1}=\frac{-6-6\sqrt{13}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{13}}{2*1}=\frac{-6+6\sqrt{13}}{2}
$